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- *Corresponding Author:
- Cusack P

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**Received Date**: December 16, 2016; **Accepted Date:** Janaury 23, 2017; **Published Date**: Janaury 25, 2017

**Citation: **Cusack P (2017) Convergence and the Grand Unified Theory. J Phys Math 8: 211. doi: 10.4172/2090-0902.1000211

**Copyright:** © 2017 Cusack P. This is an open-access article distributed under the
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This paper examines the relationship between the four fundamentals forces and shows how, using fluid mechanics, electromagnetism, quantum mechanics and gravity, these forces converge on one solution just as Mathematics does. An equation for the universal processes is provided.

Quantumn mechanics; Gravity; Convergence; Fluid mechanics; Schrodiner equation

This paper shows how as Mathematics, namely Algebra, Linear Algebra, Geometry and Calculus, converge to one solution, so too does Fluid Mechanics, Quantum Mechanics, Electromagnetism, and Gravity converge to one solution, namely the Superforce. We begin with mathematics convergence and end with Cusack’s Universal Equation. Cosmology and Quantum Mechanics are united.

We began over 4 years ago with this notion of Permeability. It still stands. It is calculated from the above equation of the circle:

2x²=tan 60°

x=√2 * √3=[(E²+t^2)1/2] *(t)=2.4495

F/2.34495=2.667/2.4495=1.08 rads

1.08 rads=62.3°

sin 62.3°=0.886=Permeability

**Prime numbers**

In the solution to the Reinmann hypothesis, the critical line for Prime Numbers is:

Y=e^{z}+Pi

The first Prime Number=1

Y=e1+Pi

Y=5.85=1/√3=tan 60°=sin 60°/cos 60°

From Geometry and the 30°-60°-90° triangle, we can see that R=1.

x²+y²=R²

2x²=1²

x=1/√2=sin 45°=cos 45°

Universal Young's Modulus=π-e1=0.4233=cuz

cuz=e^{1}+π

-e1=ez

-1=z

z is the first prime number. Mass is formed at z=-1

e^{-1}+π

=3.50

cuz²=1/81

Mass

**Eigenvectors**

Light=space. Space implies G

The rest of the universe follows at once - the crystal.

Time is a vector - an eigen vector. There is no degree of freedom with time. It flows forward and constant. It is Energy converted from PE to KE that changes with time [1-3].

11 Integrals of π=1/11! * π11=1356~s

c=d/t=s/t

s=ct

π^{10}+c=10! *π^{10}

1/t+t=11!=3.99!~0.4=1/c²

s=ten ∫ of π=ct=1/c^2* c=c

s=c

s=s'

If we Integrate π 10 times (N=10), we get space.

s=∫0-10 implies π

c=s=2.9947

2.947/2.9979=305

Light is an Eigen value; not an eigenvector. In fact, light must be what an eigen value really is. Light reaches out in a spherical way. It isn't a vector. Time is the eigen vector [4].

c=2.9979=d/t=s/t

s/t=(4/3)/ t=2/9979 (really, light is a derivative or it is 3 as it approaches max value).

t=0.4

(s/t) δt=(|E||t|sin θ)'δt

s δt *1/t δt=s δt -Ln t v-Ln t=sin 1 - Ln 1=sin 1

sin 1=δE/δt * (δt/δt)* cos t

DOT PRODUCT=CROSS PRODUCT WHEN t=1, δE/δt=1

δE/δt=sin 1/cos 1

E=∫ tan t=Ln cos t

sin sin t=cos t

E=Ln (cos t)

1=Ln (cos t)

et=cos t

derivative

et=sin t

sin t=cos t

E=1

sin-1 (0.4)=23.57 degrees

Ln (23.57 degrees)=π=Operator

The universe is an in-homogeneous Lorentz Group. There a ten real parameters.

I think where Einstein was going wrong is that he thought space and time were independent, if I understand relativity correctly. They are not. Space is the cross product of Energy and time vectors and thus completely dependent upon one another. Einstein couldn't find the Superforce because he did not know the universe is being compressed by sin theta. And of course, there is no such thing as a vacuum, at least inside the universe. Quantum Mechanics doesn't need to be recast because Einstein was incorrect. QM fits within my theory perfectly well.

Above is THE solution to Mathematics. It encompasses the 4 branches of Mathematics. It is the simplest way to explain and show the universe [5,6].

**Convergence**

The 4 branches of math: Algebra, Calculus, Geometry and Matrices are all about convergence. Where do they converge? Calculus converges on y=y'=ex. Algebra converges on the Golden Mean t²-t-1=E E=z=- 1 when t=0 • Geometry converges on the Area and circumference of a circle R=2, π, and on the Cartesian, Spherical, and Cylindrical Coordinates [7,8]. And Matrices converge on the eigenvector=√3 and eigenvalue=3 Convergence occurs at the first prime number given by Y=ez+π, z=-1.

δ2E/δt²=G

∫=δ2E/δt²=∫ G=0.4233

∫G=cuz

6.67=0.4233x

x=15.75

100-15.75=84.24 =sin θ=cos θ

∫G=cuz

6.67X=0.4233

X0.0635

1/X=15.75=1-sin θ

Integrate

Ln X=1-cos θ

Ln X=1-0.8415=0.1585

X=θ

**Gravity waves**

So with the discovery of "Gravity Waves", predicted by Einstein, I wondered if and how this discovery fits in with my theory. It does.

The collision of the black holes would be akin to a giant sink of the universal fluid. This would cause a draw down of the surrounding fluid. See illustration below.

However, I don't think that is what is happening. What is happening is that the scientists are encountering the edge of the universe. Recall that the universe is egg shaped with axes 1 x 8 x 22 or 3 x 24 x 66 LY. Consider the short axis.

3 LY * 365.25 days/ yr * 24 Hours / Day * 3600 sec/ Hr * 30,000 Km / sec=2.8188 x 10^12 km

If we consider the draw down to be exponential,

e^{2}=2.8188

Ln e^{2}=Ln 2.8188=0.4004=t

t=1/2π rads=0.4

Clairnaut:

E''-E=0

t^{2}-t-1=0 2t-1=0 2=G=E''

1/[t*G]=1/(0.4004)(2)=1.249~1.25 ~1.3 BLY

This is the distance that the Black hole collision was thought to have occurred.

So this discovery of Gravity Waves could fit in to my theory.

t=-0.618+1618=2.2236

t^{2}-t=0.1236

t(t-1)=1/81 t=1/8=0.01236

t=1/81=M

F=sin t=sin (1/81)=1/√2=sin 45°=cos 45°

As F cycles, a charge like phenomenon dissipates on the Energy parabola (Characteristic Equation or Eigen Equation). This is why we sense quantum mechanics.

G=Pi/ Ln 1.618

G *Ln 1.618=π

eG* 1.618=eπ

1/0.618=eπ/eG=eπ-G

x=1/(x-1)

x=t

eπ-G=1/t-1

E=1/t

eπ-G-t-eπ-G=1

Taking Ln of both sides,

π-G-t-π+G=0

-t=0

t=0

1/t E=Infinity

t=0, E=Infinity

Qunatum Packages are released at every cycle of π. Human Perception is freq=1/π=31.8 Hz

When the continuous charge is built up drop by drop over this time, a quantum is released. This is when the Energy of sin+cos is maximum, or its slope is 0. ∂E/∂t=0, t=1

The universe is really continuous is the Spiritual World. Humans however have evolve to sense only the E max. Why?

Q=sin θ t=1. E=1

Integral dQ/dt=Integral Pi

Q=π Q

π=Q/Q=1

=quanta

Quanta=n*1

F=sin θ

∂F/∂t=cos θ

θ=π/4=1/ ρ

t=1/ρ=E E=ρ=0.127

1602/1273=79.5~80

1/81=0.01234567

The Mass crests over at the quanta. That is what humans perceive. The world outside the human mind is continuous.

From Electromagnetism,

Jr²=cos γ

ω=∫∫ S cos γ/r² ∂a=∫∫S J ∂a

J²2=cos γ *1/r²

J² * r²/2=cos γ

The Orb is 44 cm diameter. So

[(4/3)² * (44/2)²]/2=cos γ

γ=π/2

23.704/2=cos γ

118.52=cos γ

γ=83.2°=1.452 rads

An/A=cos θ

<E,t>=|An| I

I=current=1.334

s=|An| (4/3)

An=1

-sin θ=-a=An=1/ cos θ

sin θ(cos θ)=-1

sin θ=-(1/cos θ)

-cos θ=-1/2x²

-cos=1/ 2x²

-2cos ³(t)=1

cos³ (t)=1/2

cos t=0.7937

t=37.467 degrees=6539 rads=π/ Ln 1.618=G

t=G

Now s=|E||t|cos θ

<E,t>=s=cos θ M=<E,t>

An/A=<E,t>=M

An / A=cos theta An=A cos γ n

An=A<E,t>

1/An=cos θ

1/An=4/3

A=3/4 Spherical

z=rcos θ

z=cos θ=r An

r=An

Everything in existence is relative to the number 1, even scalars.

The Unique vector that is the convergence of orthogonal subspaces is given by:

f (x)=Σ f(x) k=1 to ∞

x=f=x=^(∞+1)/ (∞+1) xx∞/∞=0.99999~1

The universe converges upon 1, where the fraction meets the multiple.

[INTRODUCTION TO SPECTRAL THEORY IN HILBERT SPACE, G. HELMBERG]

The Dot Product or Inner Product converges to the Energy Level in the universe.

<f,g>=∫ f(x) g(X) dx

=x* ∫ (1/(x-1) dx

=-2x/ (x-1)^2

If we assume the dot Product and Cross product are equal, then sin x=cos x=1/√ 2

The Quadratic, results,

x²2-0.8284x - 1=0

Solving the quadratic, know √ (-1)=-0.618,

There is only one root, and it is 0.1483. Conjugate, E=0.852

**Contraction**

[INTRODUCTION TO HILBERT SPACE, N YOUNG]

6π^{1/11}=G

G* sin 60°=1/√3

So a side of the equilateral triangle is 1/sin 60°=1/F=E

Energized is minimized when the operator is π

Contraction is shrink to an equilateral triangle. From one point to the opposite, is a 30°-60°-90° triangle.

So, the hypotenuse is 2π/√3=sin 60°* Pi=1/e (recall the energy for harmonic motion and the golden mean).

So energy is minimized.

Since e^{-t} is robust, its derivative is itself, and E=e^{t}=1, the Conservation of Energy can be expressed as:

e-t=1

Ln e-t=Ln 1

-tjj=0

So t0-(-tj)=0

t0-_tj=1

t0-0=1

t001

Strum-Liouville:

f(0)=0=f'(π)

2t-1=f'

2(3.14)-1=0.528

K.E.=1/2 Mv²

0.528=1/2 (4.482)v²

v²=23.58

Ln 23.58=π

Ln v²=π

2v=π

v=π/2

P=Mv=4.4852(π/2)=1/0.858=1/t

So why does the frequency=1/π?

1/freq=Wavelength

1/(1/Pi) sec=λ

1/s=c=d/t

d=1

c=1/1=1

d=1=c

d=c

s=d/t

s=s'

y=y'

t=1=d

t=s

t²-t-1=1 t²-t=2

Derivative

2t-1=0

t=1/2

sin θ=cos θ=1

θ=0 or π=t

t=0 is trival, so t=π

Plot Ln t and e^t and swe get our usual Rm.

δ²f/δt²+p(x) δy/δx+G(x) y=R(x)

Integrate

x³/3-x²/2-x=?

3/2* (x²-2)/2 * x -1=0

x=2.5 ~T Period

t=1/2.5=0,4=1 rad

Now inputting √2/√3=0.816 (618 in reverse)

Curvature=1/ρ=s ρ=δs/δθ 0.1273=δs/√π

δs=0.2256

1/δs=4.4320~A

A=pc/ E/s²

4.4320=2.667(4.3079)/(1/0.4233)/s²

s=0.9544

1/ρ=0.9544

ρ=1.0478 rads=60.0°

(τ')²=60 degrees=1/6

If a particle moves at constant speed, its acceleration is normal to its velocity.

In the s-t plane, normal is the acceleration, or F=sin θ

(τ')²=1/6

∫(τ²)=1/6

τ=6.3 EARTHQUAKE MAGNITUDE

Now inputting √2/√3=0.816 (618 in reverse)

3/2x²-2x-2=1/e

R(x)=1/e

This is where the Harmonic Equation meets the Golden Mean. It is our Universe!

So there are 4 fundamental forces in our material universe, namely, Strong Nuclear; Weak Nuclear; Electromagnetic; and Gravity There are all related algebraically as follows.

From above:

F=sin 1=1-1/beta

G(2A)=F+ρ/δρ *δp

G(2A)=F+1/beta

=F+ρ * δp/δρ

F=G(2A)-1/beta

δF=0 sin ρ/δp(not=) 0=1

0=dF* ρ/δρ

(1)=1+δF * ρ/δp

2GA=F+δp/δρ * ρ

δF=ρ/δρ=0

F'=0

So F=G(2A)-1/beta

F=2GA-Fd

F=1-Fd

F+fd=1

F(1+d)=1'

F=1/(1+d)

F'=[1+d)-1]'

F'=(1+d)0/0

F'=0=1/0

F'=0

1/F'=0

√(-1)/√0=sqrt (-1)=0.618, 1.618

sqrt (1/0)=sqrt (-1)

1/0=-1

F'+ρ/δp)=0

1/0+1=-0'

√(0)=1.618 0=(1.618)²=2.6179=2.618=1+1.618=t+t=2t

So, the Universe is a 4 th Order tensor with variables: F (or acceleration and its derivative momentum); t,s,E

a=v=s

s=Ae-st ..................... Temperature=mass=energy

Clairnaut harmonic bear

δ²E/δt²- E=0

G-E=0

G=∫E ...............GRAVITY

F=sin θ .......................STRONG NUCLEAR

τ=c+σ * tan(45°+φ/2)

c=-0,φ=30°, θ=45°+30°/2=60°

τ=σ * √ 3 .............ENERGY

P/e-=F/1.602=2.667/1.602=1/6=60° ........Electromagnetic

In conclusion,

E=M M=F E=G F=sin θ

F=G(2A)-1/β

and The Universal Equation is: s=E x t @ F=sin 60° s=|E||t|sin θ s=|E||t|F

Dampened Cosine In The Harmonic Beat:

Y=e-stcos θ

(1)(s)=-s* cos θ * sin θ

sin θ* cos θ=1

Taking the derivative:

-cos θ=[(cos θ)-1]'

cos θ=1

θ=0

√θ=t

t=√0=1.618

1.618/π=1/196 ∞

2.71828/π=0.865=E

[Vectors, Tensors, and the Basic Equations of Fluid Mechanics, R Aris]

1/ρ=τ²

Curvature=1/ρ=s rho=δs/δθ 0.1273=δs/√π

ds=0.2256

1/δs=4.4320~A

A=pc/ E/s²

4.4320=2.667(4.3079)/(1/0.4233)/s²

s=0.9544

1/ρ=0.9544

ρ=1.0478rads=60.0 °

τ’²=60°=1/6

If a particle moves at constant speed, its acceleration is normal to its velocity.

In the s-t plane, normal is the acceleration, or F=sin θ

τ’²=1/6

Integral (τ²)=1/6

τ=6.3 EARTHQUAKE MAGNITUDE

β=Tan u x v

β=|τ||v|sin θ

θ=60 °

v=0.2592~porosity e

β*β=1

|β||β|cos θ=1

β=√2

v'=Mv (√2) - 1/0,1273)(6.3)=4.406~A

δs/δt=0.0027

0.0227/0.8415=0.0027=υ=POISSONS RATIO

v=ρ * τ

0.02698=0.1273τ

1/ τ=0.4718

Ln τ=Ln 6.3)=1.8405

1/Ln 6.3)=0.543

0.543/0.4718=115.16

0.868

Z=sin θ sin θ=-1

z=0.8415

z=r(cos θ+i sin θ) 0.8415=r(cos 1+i sin 1) 1=r(1+i) 1/r=1+i

Z=r e(-i θ) 1.618=r(0.618)(e(-i θ)

2.6181=r(-i θ)

Ln (2.618)=0.9825=Ln (0.618)e(-i θ)

0.9825=Ln (0.618)/Ln e(-i θ)

-i θ=Ln 0.618/0.9825

i θ=Ln 0.5000 i1.618 θ=0.5

θ=0.309

θ=1.77°=√π=t

M=f=2=δM/δt

P.E.=Mgh 43.98=(2+4.486)(0.1585)(h) h=0.4233=cuz=Rm

CUSACK'S UNIVERSAL POTENTIAL ENERGY EQUATION

P.E.=[M+δM/δt][u.g.)(R_{m})

K.E.=1/2 Mv²

=1/2 (2+δM/δt)v²

=(2+4.486)(0.8415)²=2.2964

Ln K.E.=3.1339~π

tan P.E. / K.E.=1397°

E=0.8603

tan φ=cot φ

φ=1.599=1/6

φ0.625 rads

'tan (45°+φ/2)=88.4=h

45°+φ/2)=35.82°

φ=16164~1.618=t on the Energy Golden Mean Parabola

[J. Bear Fluid Dynamics in porous Media]

β=1/ ρ * δρ/δp

=s*δρ/δp

=4/3* (0.1273)/26.667)

=0.0636

=Earthquake Magnitude

1/ β=15.72

1-1/β=0.8428=sin 1

F=sin 1=1-1/ β

And,

Permeability

1-Kz/b=sin 1

kz/b=Moment

kz/b=Fd

d=z

k/b=F

15.85=26.667 (b)=k

k=0.5944

1/k=1682

1/k=1.7

s=k*ρ=1.7(0.1273)=1333=s

s=k 1/s)

s^2=k

k=1.77=√π

s=√[√π]]

t=π

t=√θ

√θ=π \\√[√π]]=√π

s=√√π

s4=π

s4=(1+e)=1.263

T=kb=(0.5944)(0.0594) 0.0353

τ δτ/δt=kT/s

√3 * δτ/δt=(0.5944)(0.0353)/(1.263) δτ=√3=1/6

δτ/δt=δE/δt=∫ G=1/6/√3=0.0962

∫G=∫δτ/δt=τ

G²/2=τ=0.0962

G=0.4386=P.E.

G=43.86(2/3)=15198

K.E.=8480

K.E.=1/2Mv²

M=2=F

M0=F * d=0.1585=sin θ* s

0.1585/(4/3)=sin θ

sin θ=118.9 (118 Chemical Elements in the Periodic Table)

4.486/ (118.9* 938)=402.11=Re

Re/ sin θ=Mp+/M Re=Inertia f / Visc F=sin (0.1696)/ sin (0.2699)=6.383~h=2/Pi h=(δM/δt)/ t δM/δt=ht

2=6.36*t

t=π

This is the solution to Mass degeneration in QM.

C=A'=2πR

M0=F*d=F*R=sin θ * δR/δt=δM0/δt

I=δM0/δt=sin θ * δR/δtt=δR/δt

tδt=δR

∫t dt=∫ δRdt t²/2=R

t²/2=R t=2

t²-t-1=E δE/δt=2t-1=G

2(2)-1=3=c

1/c=Wa. Eq.

δM/δt=G=δ²E/δt²

So Gravitational Constant is the rate of Mass degradation (and formation)

M=1/81~0.125

∫δM/δt C_{0}=∫ M

M* 1.602=M²/2

C=251=T Period

So, what governs δM/δt=0.197?

E=Mc²=F

F=sin θ=Mc²

sin t=197 (2.9979)²

=1.77=√π=√t

t=1/T

1=1/251=0.4

√4=2=R

δM/δt=R

A'=2πR=2π(2)=4π

So the rate of change=1/4π=0.796~0.8

Or

81=c4

δc4/δt4=δ3 v/δt³=δ²s/δt=C=T Period

So, Mass degrenrates at the Period T=251/sec

M=sin t-e^{(1696 *R²)}

δM/δt=cos t-e^{(0.1696*4)}

=0.6609-0.507

=0.4283~cuz

0.4283*0.1978=0.847

1/0.847=118 Elements in the Periodic Table.

There are 7 Periods in the Periodic table of the Elements.

Wa. Eq.=1.618(7*R²)

28Ln 1.618=1/23=4.3482

M/c=28/2.974=941.5=Mp+

p=hk=hF=6.36*2.667=0. 1696

4.3482/c=1.48~1.5

e-1.5=M

E=Mc² E=M/c * c³

E/c³=epR/c³=e^{(1.696)(2)}=1/81

1/81=0.012345679

This then is how Mass and the Period table and the Wave Equation are interrelated. It also shows the Mass Gap.

p=hk=hF=6.36(8/3)=1696

F-∫ψe^{(π/2)}=e^{(pR²)}

CUSACK'S QUANTUM CHEMISTRY FORMULA

M=sin (1/E)-e^{(pR²)}

ψ=[Gt³-1/R * t²-t]e^{(t/2)}

Let t=c=3

ψ=[2/3(3³)-1/2(3²)-3](e-3/2)

=1/c

1/c=E

E=1/t

**Wave equation**

U=iV=1+(0.618* 1)=1.618

1.618=1/√ (2π* e^{k})

k=405

k=1.4001

0.86 or 59.3 degrees~ 60 degrees

Is matter a wave or particle? I'd say a wave creates a particle. A wave is a form of energy. That energy is stored in the mass. Thus E=Mc². The sine curve is the Force which equals Energy that is put into Mass formation. The Mass is a temporary store for P.E. Einstein's Equation should be, PE=Mc^{2} So, F=E as we have already calculated.

t2-t-1=E=sin t=1/√2

t2-t=1/√2+1

t(t-1)=1.707

t=1.707=1+1/√2 OR, t=2.707~e1

t=1+sin 45=1-sin t=Moment OR t=E

E=1/t

[QUANTUM THEORY DAVID BOHM]

**Quantum theory**

The Fourier Integral is the dampened cosine curve already introduced.

The pulse of the universe is like a heart beat, one dampened cosine curve after another.

Y=e-t cos θ

Y'=et sin θ

y=y'

cos θ=sin θ

Wave Equation=1/ √2 / √π* Integral ek ∂k

=1/√π * cos 45° ek

=1/ √π * Y

1/√π * cos 45°=0.3991~4

4=SUM (E+t) (Vector Space)

THIS UNITES COSMOLOGY WITH QUANTUM MECHANICS.

So we've unified Cosmology with Quantum Mechanics and Electromagnetism. That is the Grand Unified Theory.

Quantum mechanics

INTRODUCTION TO QUANTUM MECHANICS, D J GRIFFITHS]

ψ==cn ∫ (t²-t-1)* e^{(t/2)}

CUSACK'S MODIFIED SCHRODINGER EQUATION

ψ=[Gt³-1/R*t²-t] e(π/2)]

OR,

E=∫ E e(t/2) where t=π

deBroglie Wavelength

λ=h/ √[3MkT]

=h/ √[3* 4.482*8/3*0.2506]

=h/c²

=1//√2=sin 45°=cos 45° (45°=1 qusackian)

If we have 5 singular points for a Linear Second Order Differential Equation, we have the famous distance equation:

d=v_{i}t+1/2 at²

Integrate this twice, we get 6 variables (s, G, d,v,a, M), From the Clairnaut Second ODE, we get the Operator (frequency) , and the Energy, All we need is R_{m}=cuz and N=11

I've shown already that sin must equal cos for matter to appear. Now I tell you that the Fourier Integral converges on G=2/3 when sin=cos or y=y' x=0.8415=sin 1 L=87 & 8.7& 0.87 n=1 a_{0}=0

a_{0}/2+Σ [a * cos (nπx/L)+b sin(nπ x/L_{0}]

a=1/L ∫ f(x) cos (nπ x/L) dx

=-sin (nπ x/L)

b=1/L ∫f(x) sin (nπ x/L)

=cos (nπ)/L

Substituting,

0/2+∫(-cos² (nπ x/L)+sin ² (nπx/L )

2/3 sin³ (nπ x/L)+2/3 cos³ (nπx/L)=-2/3 (sin³((1)(π)(0.8415/ 87))+2/3 cos³ ((1)π*0.8415)/87)

=0+2/3 (1)=2/3=G

F=G c* GE F=G(c+E). The solution to the Fourier Integral is necessary (y=y'=et) and sufficient.

CUSACK'S MASS FORMULA M=2πR/cuz/C0 One only needs the Fourier Integral, the Orthogonal Matrix with Operator Ω^-1=1/π, and Cusack's Mass formula to sole the entire Universal Problem.

CUSACK'S FORCE EQUATION

F-G=sin 60°

A'=Circ=2πR

R=2=δM/δt=E=G

2π*2=4π

4π/cuz=29.6867

29.68/C0=29.6867/1.602=1853~ n/p+

1853 * 7=129.71=1/0.771

0.771*24* 3600=6.67=G

E=Ω-- Ω_{0}=2π/l

=2π (0.75)=8/3 * π=F* t=I

∫qa/dE=(qa)²/2* dt

=7^2/2* dt=992

dt=40489=23.1985 rads

Ln 23.1985=3.1441~π

Bell Curve:

ψ=1/ √2π] * ∫e-t

Let t=π

1/ Te-πt*e^π=tE=172~√ 3=E

E=Mt tE=Mt²

E=√3

t=1.618=ψ

No spooky action at a distance.

So the process that governs QM is not subject to a hidden variable. It is 1`/81=0.012345679

ΔE=hv=6.36 (1/π)=202.45

Σqa / dE=qa)²* dE

=7^2* 202=992

1/992=1.0081=H+

God doesn't roll the dice.

d/dx csc=csc 2.9979+cot 2.9979=19.126-19.100=365.3=Earth Year

2.9979 * 365=1 LY

And,

[David Bohm, Dover]

E=1/ (8π) * ∫ (Electric field^2+Magnetic Field) dr

=19905 / (8π)* R

=1584~1-sin 1=Moment=F* d=Work

So the Universe of volume 19905 is an Electric and Magnetic field.

δ²E/δt²-E=Ln t

or,

GE³-Ln t=s

0.666*E³-Ln 1=||E||||t||cos 60°

E=1.2533

E=-1.2533=Emin=t^2-t-1 (GOLDEN MEAN)

You might do a sensitivity analysis on this circuit?

x²-y^2=π

2x²=π

x=√π/√2

x²-x-1=1-0.625=1/π=31.8Hz (Human Perception)

The capacitor should be C=π

V=iR G||E||||t||cos 60°=[r+1/c+L]i

R=slope m=1/cuz 1/C=Pi L=2

G*0.8415*sqrt3/2=[π-e+π+0.8415(√3/(2c²)]i

G*unit eigenvector=1 cycle –e+sin 1 unit eigenVector/[2 unit eigenValue²]

G * unit eigenvector=3Pi-2e+eigen vector/eigen Value²

G*unit eigenvector=eigenValue Pi+δM/δt*e+eigenvector/eigen value²

The universe is where the FUNCTION x²-x-1=0 meets the RELATION x²-y²=1

The FUNCTION is the Derivative whereas the RELATION is the Integral. So y=y’=Integral y=e^{x}

Since 0.618=sqrt 1, and this is imaginary, it follows that 1/0.618=1.618 is imaginary. 1.618*0.618=1 is imaginary. The energy that makes up the universe is imaginary. We are all but images in God’s mind.

We see that the Cusack Universal Equation and the Cusack Force Equation unites the four fundamental forces in our universe -the Holy Grail of Physics. There is no sooky action at a distance and Quantum Mechanics and Cosmology are finally united.

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- Bear J (1972) Fluid dynamics in porous media.Dover, New York.
- Ohm D (1951) Quantum theory.Dover, New York.
- Cusack P (2016) Riemann Hypothesis Clay Institute Millennium Problem Solution. J Appl Computat Math 5:317. doi:10.4172/2168-9679.1000317.
- Griffiths DJ (2014) Introduction to quantum mechanics. Pearson Essex,England.
- Helmberg G (1969) Introduction to spectral theory in hilbert space. Dover, New York.
- Ronjansky V (1971) Electromagnetyic fields and waves. Dover, New York.
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