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Generalized Lie Theory and AT Math | OMICS International
ISSN: 1736-4337
Journal of Generalized Lie Theory and Applications
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Generalized Lie Theory and AT Math

Paul TEC*

BScE, DULE, 1641 Sandy Point Rd, Saint John, NB Canada

*Corresponding Author:
Paul TEC
BScE, DULE, 1641 Sandy Point Rd
Saint John, NB Canada
E2K 5E8, Canada
Tel: (506) 214-3313
E-mail: [email protected]

Received date: February 07, 2017; Accepted date: March 23, 2017; Published date: March 29, 2017

Citation: Paul TEC (2017) Generalized Lie Theory and AT Math. J Generalized Lie Theory Appl 11: 262. doi: 10.4172/1736-4337.1000262

Copyright: © 2017 Paul TEC. This is an open-access article distributed under the terms of the Creative Commons Attribution License, which permits unrestricted use, distribution, and reproduction in any medium, provided the original author and source are credited.

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Abstract

Here we provide the step by step procedure to end that the Generalized Lie Theory converges to one solution, that is the Universe. We consider the Hyperbola; Rotation Matrix, the Cross and Dot Products; Euler’s formula, Communicator, and Astrotheology Mathematics. They all converge to one final solution.

Keywords

Unit hyperbola; Orthogonal rotation matrix; Cross product; Euler’s formula; Communication; Clairnaut; Golden mean parabola; Ln function; Resistance to mass

Introduction

In this brief paper, e being by considering the various components of Generalized Theory. We see they all converge upon one solution, namely, the Astrotheology Model of the Universe. This paper consort is properly understood until the reader is familiar with the AT Math.

Unit hyperbola

X²-Y²=1

cos ² (π/4) - sin ² (π/4)=1

Orthogonal rotation matrix

A=|cos θ sin θ|

|-sin θ cosθ|

|A|=1 when θ=60° Superforce=sin 60° [1]

Cross product=dot product → Space s [2]

s=|E|t|sin θ

E=1/t

s=(1)(1)sin (π/4)

=1/√2=sin 45°=cos 45° → Dot Product=Cross Product

θ=π/4=45°

Euler’s formula

cos² (45°)+ i sin(45°)=eit

i=-0.618 Let t=2 communicator t=2=Vector [3]

E=e(0.618)(2)=1/0.809=1/c4=0.12345679

(1/√2)²+(-0.618)(1/√2)²=1/2.9997=1/c

1/c=(1/c4)0.250)

T=0.250=1/t==>t=0.4=1 rad t=1

Clairnaut differential equation [4]

y=y’=y'’=s=v=a=(-sin θ)=cos θ and d²E/dt²=G [1]

d²E/dt² -E=0

∫∫d²E/dt²=∫∫E

∫∫G=E³/3

G³/3=E

6.67³/3

=9.89

=E=1/t

t=1/0.989=1.01~1

Golden mean

t²-t-1=E

(1.01)²-1.01-1=0.9899=1/1.01=dE/dt

LN function

dE/dt=1 when t=1 and E=0 → Conservation of Energy (Figure 1).

generalized-theory-applications-exponential-functions

Figure 1: The Ln and exponential functions.

E=e-t

=e-1

=1/e

cf. Dampened Cosine

Y=e-t cos (2πt)

Let Y=E and t=1

E=Y=e-1 cos (2π)

E=1/e

And E=e=0.04321

1-E=1-0.0=1=E

1-1/t=1/t

1=2/t

t=2

Golden mean

(2)^2-2-1=1=E E=1 and t=2

E=e-t-Rm=0.43214-cuz=0.0084=ε0 → Permittivity of space

Ln (0.884)=0.123=1/c4=eit where i=0.618 and t=2

Resistance to mass formation

Rm=(π-e)=cuz=(t-E)

(t-E)=Y=E

t=2E

E=1=t/2 →t=2 vector

Golden mean equation

1+t=t

(Note: For the Dampened Cosine, Y=e^t cos (2Pit),, E=1/t=1 when t=1,, Y=0.202 at the beginning of the dampening or t=0. Another way, when the Ln function crosses the x axis at t=1, the dampened cosine begins, or t=0).

Derivative

0+dt/dt=dt/dt

0+1=1 True!

1+t=t

(t+1)/t=t

t²=t+1

t²-t-1=0 →Golden Mean Equation.

Conclusion

The solution of Generalized Lie Theory converges to the Specialize Lie Theory, or Astrothoelogy, Cusack’s Universe.

References

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