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Received Date: March 02, 2017; Accepted Date: April 22, 2017; Published Date: April 25, 2017
Citation: Cusacki PTE (2017) More on the Robust Solution for Epidemiology: Nineteenth-Century Quebec. J Biom Biostat 8: 342. doi:10.4172/2155-6180.1000342
Copyright: © 2017 Cusacki PTE. This is an open-access article distributed under the terms of the Creative Commons Attribution License, which permits unrestricted use, distribution, and reproduction in any medium, provided the original author and source are credited.
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Here we consider the Robust Solution as applied to the cholera epidemic in Lower Canada (Quebec) in 1832. We find that the mathematics from that procedure provides the mathematical foundation or the study. The rate of growth of the virus must be kept below 14% to terminate the spread of the disease.
Energy; Time; Density; The bell normal; The golden mean parabola
This paper is an examination of the mathematics already wellestablished as the Robust solution. We use this solution applied to the cholera epidemic, particularly in what is toddy, Quebec-Montreal and Quebec City. The data was found in Bilson’s book, A Darkened house, Cholera in nineteenth Century Canada. Some figures come from the Saint John Cholera epidemic 1854 [1-3]. We begin there.
In Saint John, 1854,
1103 deaths from Cholera/pop. 30,000=1/e=e^-t=E
In Quebec 1832-33:
X=1269=rho=density ~ 4/Pi
Now rho/c=126.9/2.9979=0.4235 ~ Pi-e=0./4233.=Resistance to Disease=Rd
Rho/c* Pi=Space s
And, from Astro-theology mathematics:
The cross-product vector is:
Resistance to death=(Vd) (Cycle)cos (Cycle)
=e*(40% of a cycle) cos (1 rad)
1-54.18%=45.82% ~ 45.7=death rate in the entire province of Quebec
Cf Average Death rate above=41/1000.
395=S.D.=Sqrt [(1/N) SUM (X-Xbar/S.D)]Let S.D.=Re=395, and solving:
1560 N=G X^3-X^2-X
Phi=1/Sqrt(s*2Pi) e^-1/2 (X-0.7)/0.3)^2
X=0, 1.4 for mew=0.7
1.2 * c^2=1.08=Z score for 85.99% 1/85.99=116.29=Mass no of elements in the periodic table.
1-0.8599=0.14=14% minimum profit to sustain growth.
Root for the Bell Normal.
Φ=1/√(σ2π) e-1/2 [(X-1.30/1.30)]²
=99.125=1/1.009 ~ 1.01=E
Roots X=0, 1.4
0 ≤ X ≤ 1.4
1/81.99=116.29=Mass of final element in periodic table.
Y=e-t cos t
116.29=e-t cos t
Refer to Figure 1.
At t=0, Ln t=0
Ln π+cuz=2.568 ~ π/2=t/2
G ~ 6.54=1/et