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**Cusack PTE ^{*}**

Eng Dule, 1641 Sandy Point Rd, Saint John, NB E2K 5E8, Canada

- *Corresponding Author:
- Paul TE Cusack

BSc, Eng Dule, 1641 Sandy Point Rd, Saint

John, NB E2K 5E8, Canada

**Tel:**(506) 214-3313

**E-mail:**[email protected]

**Received date:** January 01, 2017; **Accepted date:** February 08, 2017; **Published date:** February 14, 2017

**Citation: **Cusack PTE (2017) The Western Pacific Biotwang: Experimental Evidence forstrotheology - Cusack’s Universe. J Astrophys Aerospace Technol 4:136. doi:10.4172/2329-6542.1000136

**Copyright:** © 2017 Cusack PTE. This is an open-access article distributed under the terms of the Creative Commons Attribution License, which permits unrestricted use, distribution, and reproduction in any medium, provided the original author and source are credited.

**Visit for more related articles at** Journal of Astrophysics & Aerospace Technology

In this brief paper, I consider that the mysterious sound frequencies heard in the Western Pacific are not from belugas, but rather are the internally reflected waves from the Super force heard at the ocean bottom in the Marina Trench. These waves travel through the Ether which comprises the universe. They are intensified by the mass of the Earth. This could prove to be the first experimental sign of the Astrotheology theory of the Universe.

Mariana trench; Western Pacific, Biotwnang; Super force; Waves; Earth

Sound frequencies heard in the Mariana trench range from 38 Hz to 8000 Hz. I provide here a possible explanation for these sounds [1]. The answer lies in the Astrotheology Model of the Universe. They are not whale mating calls but evidence for the Astrotheology Cosmos theory. I refer the reader to the paper Astrothoelogy, Cusack’s Universe to get an understanding of the calculations included herein. See References for the paper and associated textbooks [2,3].

First, we look at the 8000 Hz:

8000 Hz = 1/(125 × 10-6)

We will work with 125

Emin = -1.25 is the minimum of the energy time parabola.

T²-t-1 = 0, 2t-1 = 0, t = ½, E = -1.25

Emin* t = -1.25 * 1/-1.562 = 1563.

Moment = 1- sin 1 = 1-0.1563 = 0.8437 = sin 57.5 deg. = 1.0004 rad ~1 rad = t = E.

Period T = 251.2 sec.

As shown in **Figure 1**, the Super force sine wave is reflected internally within the Earth.

The Earth has a radius = 6371 km.

Therefore its diameter = 12742 km. This is a boundary condition of the Super force.

1 rad/2Pi = = 0.1592 = 1-sin 1 = moment.

E = e-0.1592 = 203.5~202.8 = Y.

12742 = 2π rads for a reflected sine wave inside the Earth’s mass.

1 rad = 12742/(2π) = 2027. 895 is ~Y = Energy = Dampened cosine curve.

The Energy Y, dampened out in the density of the ether of the universe [3].

Consider the following:

**The dampened cosine curve**

Y = e-t cos t = 202.8

cos ² t = 0.202795-1

= 0.7972

Solving for t,

Trig. identity

sin² t+cos²t = 1

sin²2 t +(0.202.8/t)² = 1

Solving this quadratic,

t sin² t = 0.7972

-t cos t = 0.2028

-sin²t = 3.9311 cos t

**The Euler’s identity**

Sin ² t+cos ² t = 1

-sin ²t = -1+ cos² t

-1+cos²t = 3.9311 cos t

Cos²t-3.9311 cos t-1 = 0

Solving this Quadratic,

x²-3.9311 × -1 = 0

x = 4.1709, -0.2398

Ln (2398) = 3.17~31.8 = frequency = Human Perception = 1/Pi = 1/t

And, the Mass of a proton absorbs the vibration:

x = cos t

-0.2398 = cos t

t = 103.87° = 1.8132 rads.

Sin 103.287 = 0.9708

Sin t/cos t = 0.404~0.402 = Re

sin² (1.8132) = 0.9424 = Mp+

cos² (1.8132) = 1/ 1.73558 = 1/√3 = tan 30° = cot 60°

Ln 1.8132 = 0.595~0.6

e-1.8132 = 1631~1623 = M p+

**Reynold’s number, mass and density for the ether**

Re = ρvL/μ

0.404 = ρ(0.707)(4/3)/ 0.27)

ρ = 115.7~116 = Elements in the Periodic Table = Mass.

1/ρ = 0.8643

Sin -1 (0.8643) = 59.80°~60° (Critical Angle).

1.0436/1.8132 = 1.7375~√3 = t (Eigen vector).

(8000 Hz) 0.404 = (128.6)(0.8415)(4/3)/(0.27)

Now, considering the low end frequencies 38 Hz of the Biotwang:

Super force = F = 2.667 = 1/37.495~38 Hz

**Density of the material**

Radius of the Earth = 6371 km

6371/Pi = 202.79 = Y

Y = 2.0279 = e^-1 cops t

Ln (2.0279) = Ln e^-t + Ln (cos t)

0.707-1 = Ln (cos t) (note: 0.707 = 1/sqrt 2 = sin 45 = cos 45 = a = v **→** y = y’)

T = 72.9 degrees = 127.3 rads = rho = density

Re = rho v /nu

(127.3)(0.8415)/0.27 = 396.75

= 1/252 = 1/Period T = 1/E = t

T = rho

T*c = 396.75 (2.996) = 118.6~ 118 Elements in the period table.

**Speed of light - The wave velocity in the material**

The Biotwang has duration of 3.5 seconds. Refer to (**Figure 2**). This is proportional to the speed of light, c, or the velocity of the wave in the ether reflected by the mass of the Earth.

We know, E = √Period = √T

√T = E

√T is proportional to c²

√T = 8976

T = c4

T = 80.5

1/T = 1/t = E = 1/80.5 = 0.12345679

80.5/3.5 sec = 23

Ln 23 = π

And, √T/2 = c

T = 92)(8.976) = 17.95~18

Earth’s Diameter = 12,742 (**Figure 1**).

12,742/ 3.5 sec = 18.2 cf 18 = T

Radius of the Earth = 6371 (π) = 2.0015

Y = e^-t cos t

200.15 = e^-t cos t

Ln (2.0015) = -1+cos t

0.6939-1 = cos t

t = 1.2597 rads = 7938 Hz~8000 Hz.

The mysterious sounds heard in the Western Pacific may be internally reflected waves form the Super force. This observation could be proof of the Astrotheology theory of the universe.

- Tawbrey FJA, Thomas RA (1988) Kasstein low frequency underwater in Belugas
- Cusack P (2016) Astrotheology: Cusackâ€™s Universe. J. of Physical Mathematics.
- The Ether(2016) Theuniversal material. Fluid mechanics, Open Access OMI.

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